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Actually, I can tell you how much power is required to defeat the rolling resistance and drag (assuming that the wind-speed is 0MPH!): NOTE: I couldn't find the frontal surface
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A True Z Fanatic
Join Date: Dec 2008
Location: Los Angeles
Posts: 1,853
Drives: 02 Corvette Z06
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Actually, I can tell you how much power is required to defeat the rolling resistance and drag (assuming that the wind-speed is 0MPH!):
NOTE: I couldn't find the frontal surface area on the 370z, so I'm GUESSING it's around 1.9m^2. It could be less. First figure out how much drag force there is: F_drag = (Drag Coefficient) * (Frontal Area-meters) * (Volocity-Km/s)^2 200MPH = 89.42Km/s F_drag = 0.29 * 1.9 * 89.422 = 4405.76 N Now we figure out the rolling resistance: F_tire = (Vehicle Weight-Kg) * 9.8 * (drag_contribution) F_tire = 1506 * 9.8 * 2.43% = 358.64 N Now calculate how much power is needed to push against these forces: P = F * V P = 4764.4 * 89.42 = 426032.648 Watts = 571.32HP So, approximately 571HP is needed to get the car to 200MPH
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